Solving Rectilinear Problems - Example Problem 2.2-3
A car is driving along a straight road at 60 mph. The driver suddenly applies the brakes decelerating the car at a constant rate of 10 ft/s2. What is the stopping distance of the car? If the deceleration of the car is a function of the distance traveled and given by a = -√s ft/s2, where s is in ft, what is the stopping distance of the car in this case?
Given:
- v0 = 60 mph
- vstop = 0
- a) a = -10 ft/s2 = constant
- b) a = -√s ft/s2
Find:
- sstop
Solution:
The following video walks you through the solution to this problem. It is suggested that you try solving the problem first and then, if you have difficulties with the solution, watch the video for help.
In the first part of the problem (part a), the deceleration of the car is constant, therefore, we can use the constant-acceleration equations.
Based on the information given, which equation should we use to find the car's stopping distance?